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AD<Base> y(x)
AD<Base> y = x
y = x
AD<Base> object y
and the assignment operator uses an existing y.
In either case,
y has the same value as x,
and the same dependence on the
independent variables
(y is a
variable
if and only if x is a variable).
const Type &x
where Type is
VecAD<Base>::reference,
AD<Base>,
Base, or
double.
AD<Base> &y
| CopyAD.cpp | AD Copy Constructor: Example and Test |
| CopyBase.cpp | AD Constructor From Base Type: Example and Test |
| Eq.cpp | AD Assignment Operator: Example and Test |